Two spherical bodies of mass M and 5M and rad | vedclass

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Question

As the spherical bodies have their own size so the distance covered by both the body $12 \mathrm{R}-3 \mathrm{R}=9 \mathrm{R},$ but individual distanc

Vedclass · Accepted Answer

$7.5\, R$

Vedclass · Answer

As the spherical bodies have their own size so the distance covered by both the body $12 \mathrm{R}-3 \mathrm{R}=9 \mathrm{R},$ but individual distance covered by each body depends upon their masses.

We know that bodies are moving under the effect of mutual attraction only, so their position of centre of mass remains unaffected.

Let smaller body cover distance $x$ just before coll ision From $\mathrm{m}_{1} \mathrm{r}_{1}=\mathrm{m}_{2} \mathrm{r}_{2},$ we get

$\Rightarrow M x=5 M(9 R-x) \Rightarrow x=7.5 R$

Two spherical bodies of mass $M$ and $5M$ and radii $R$ and $2R$ respectively are released in free space with initial separation between their centres equal to $12\,R$. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is

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