Two solutions of electrolytes X and Y are tak | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molar conductivity $(\Lambda_m)$ of an electrolyte depends on its degree of dissociation. For a strong electrolyte,the degree of dissociation

Vedclass · Accepted Answer

$X 	o NaCl, Y 	o CH_3COOH$

Vedclass · Answer

(B) The molar conductivity $(\Lambda_m)$ of an electrolyte depends on its degree of dissociation. For a strong electrolyte,the degree of dissociation is already near $100\%$,so dilution causes only a small increase in $\Lambda_m$ due to the reduction in inter-ionic attractions. For a weak electrolyte,dilution significantly increases the degree of dissociation,leading to a sharp increase in $\Lambda_m$. In this case,$X$ shows a small increase ($1.5$ times),indicating it is a strong electrolyte (e.g.,$NaCl$). $Y$ shows a large increase ($20$ times),indicating it is a weak electrolyte (e.g.,$CH_3COOH$). Therefore,$X$ is $NaCl$ and $Y$ is $CH_3COOH$.

Two solutions of electrolytes $X$ and $Y$ are taken in two beakers and diluted by adding $500 \ mL$ of water. The molar conductivity $(\Lambda_m)$ of $X$ increases by $1.5$ times,while that of $Y$ increases by $20$ times. What could be the electrolytes $X$ and $Y$?

Similar Questions

What is the relation between cell constant,conductivity and electrical resistance?

What is the effect of dilution on the equivalent conductivity of a strong electrolyte?

The electrical resistance of a column of $0.05 \ mol \ L^{-1}$ $NaOH$ solution of diameter $1 \ cm$ and length $50 \ cm$ is $5.55 \times 10^{3} \ \Omega$. Calculate its resistivity,conductivity and molar conductivity.

What is the conductivity of $0.01 \ M$ $NaCl$ solution if the resistance and cell constant of the $NaCl$ solution are $375 \ \Omega$ and $0.5 \ cm^{-1}$ respectively at $298 \ K$?

How does the conductivity of a strong electrolyte change upon dilution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module