Two sides of a triangle are given. If the are | vedclass

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(D) Let the two given sides of the triangle be $a$ and $b$,and let $	heta$ be the angle between them.The area $A$ of the triangle is given by the for

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$90$

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(D) Let the two given sides of the triangle be $a$ and $b$,and let $	heta$ be the angle between them.The area $A$ of the triangle is given by the formula $A = \frac{1}{2} ab \sin 	heta$.Since the sides $a$ and $b$ are fixed,the area $A$ depends only on $\sin 	heta$.For the area to be maximum,$\sin 	heta$ must be at its maximum value.The maximum value of $\sin 	heta$ is $1$,which occurs when $	heta = 90^{\circ}$ or $\frac{\pi}{2} 	ext{ radians}$.Therefore,the angle between the given sides for the maximum area is $90^{\circ}$.

Two sides of a triangle are given. If the area of the triangle is maximum,then the angle between the given sides is (in $^{\circ}$)

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