Two short magnets of magnetic moment 1000 , A | vedclass

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(A) Point $P$ lies on the equatorial line of magnet $(1)$ and the axial line of magnet $(2)$ as shown in the figure.The magnetic field due to magnet $

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$0.1$

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(A) Point $P$ lies on the equatorial line of magnet $(1)$ and the axial line of magnet $(2)$ as shown in the figure.The magnetic field due to magnet $(1)$ at point $P$ (equatorial position) is:$B_1 = \frac{\mu_0}{4\pi} \cdot \frac{M}{d^3} = 10^{-7} 	imes \frac{1000}{(0.1)^3} = 10^{-7} 	imes \frac{1000}{0.001} = 10^{-7} 	imes 10^6 = 0.1 \, T$The magnetic field due to magnet $(2)$ at point $P$ (axial position) is:$B_2 = \frac{\mu_0}{4\pi} \cdot \frac{2M}{d^3} = 10^{-7} 	imes \frac{2 	imes 1000}{(0.1)^3} = 10^{-7} 	imes \frac{2000}{0.001} = 10^{-7} 	imes 2 	imes 10^6 = 0.2 \, T$Since the fields $B_1$ and $B_2$ are in opposite directions at point $P$,the net magnetic induction is:$B_{	ext{net}} = B_2 - B_1 = 0.2 \, T - 0.1 \, T = 0.1 \, T$

List-$I$	List-$II$
$(A)$ Magnetic induction	$(I)$ Ampere meter$^2$
$(B)$ Magnetic intensity	$(II)$ Weber
$(C)$ Magnetic flux	$(III)$ Gauss
$(D)$ Magnetic moment	$(IV)$ Ampere meter

List-$I$	List-$II$
$(A)$ Magnetic field intensity	$(i)$ $Wb$
$(B)$ Magnetic flux	(ii) $Wb \cdot m^{-2}$
$(C)$ Magnetic pole strength	(iii) $A \cdot m$
$(D)$ Magnetic induction	(iv) $A \cdot m^{-1}$

Two short magnets of magnetic moment $1000 \, A m^2$ are placed as shown at the corners of a square of side $10 \, cm$. The net magnetic induction at $P$ is....$T$

Similar Questions

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$(A)$ Magnetic induction $(I)$ Ampere meter$^2$
$(B)$ Magnetic intensity $(II)$ Weber
$(C)$ Magnetic flux $(III)$ Gauss
$(D)$ Magnetic moment $(IV)$ Ampere meter

Choose the correct answer from the options given below:

For a ferromagnetic material,the relative permeability $(\mu_r)$ versus magnetic intensity $(H)$ has the following shape:

Magnetostatic screening or shielding can be created by

Two identical bar magnets are fixed with their centres at a distance $d$ apart. $A$ stationary charge $Q$ is placed at $P$ in between the gap of the two magnets at a distance $D$ from the center $O$ as shown in the figure.

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