Two seconds after projection a projectile is | vedclass

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Question

$T=6 s$

$\frac{24 \sin 	heta}{g}=6$

$u \sin 	heta=3 g$

$u \sin 	heta=3 g$

$u \cos 	heta=\sqrt{3 g}$

$	an \alpha=\frac{u \sin 	het

Vedclass · Accepted Answer

$20\sqrt {3\,} \,\,m/s\,,\,\,{60^o}$

Vedclass · Answer

$T=6 s$

$\frac{24 \sin 	heta}{g}=6$

$u \sin 	heta=3 g$

$u \sin 	heta=3 g$

$u \cos 	heta=\sqrt{3 g}$

$	an \alpha=\frac{u \sin 	heta g t}{u \cos 	heta}$

$	an 30^{\circ}=\frac{3 g-g \cdot 2}{u \cos 	heta}$

$u \cos 	heta=\sqrt{3} g$

$	herefore 	heta=60^{\circ}$

$\mathrm{u}=20 \sqrt{3} \mathrm{m} / \mathrm{s}$

Two seconds after projection a projectile is travelling in a direction inclined at $30^o$ to horizontal, after one more second it is travelling horizontally. What is the magnitude and direction of its velocity at initial point

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