Two satellites of equal mass are revolving ar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The areal velocity of a satellite is given by the formula: $\frac{dA}{dt} = \frac{L}{2m}$,where $L$ is the angular momentum and $m$ is the mass of

Vedclass · Accepted Answer

$3/4$

Vedclass · Answer

(A) The areal velocity of a satellite is given by the formula: $\frac{dA}{dt} = \frac{L}{2m}$,where $L$ is the angular momentum and $m$ is the mass of the satellite.Since the masses of the two satellites are equal $(m_1 = m_2 = m)$,the ratio of their areal velocities is directly proportional to the ratio of their angular momenta.$\frac{(dA/dt)_1}{(dA/dt)_2} = \frac{L_1 / 2m}{L_2 / 2m} = \frac{L_1}{L_2}$.Given the ratio of angular momenta is $L_1 : L_2 = 3 : 4$,the ratio of their areal velocities is $3/4$.

Two satellites of equal mass are revolving around Earth in elliptical orbits of different semi-major axes. If their angular momenta about the Earth's center are in the ratio $3:4$,then the ratio of their areal velocities is ........

Similar Questions

What is the orbital velocity of a satellite? Derive its equation.

$A$ geostationary satellite:

Suppose the gravitational force varies inversely as the $n^{th}$ power of the distance. Then,the time period of a planet in circular orbit of radius $R$ around the sun will be proportional to

$A$ satellite of mass $M$ is revolving in a circular orbit of radius $r$ around the Earth. The time period of revolution of the satellite is:

Two satellites of masses $m$ and $3\,m$ revolve around the earth in circular orbits of radii $r$ and $3r$ respectively. The ratio of orbital speeds of the satellites respectively is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module