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(C) The acceleration due to gravity $(g)$ at the surface of a planet is given by the formula: $g = \frac{GM}{R^2}$.Here,$M$ is the mass of the planet

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Greater on the larger planet

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(C) The acceleration due to gravity $(g)$ at the surface of a planet is given by the formula: $g = \frac{GM}{R^2}$.Here,$M$ is the mass of the planet and $R$ is its radius.Since the planet is a sphere,its mass can be expressed in terms of its density $(ho)$ and volume $(V)$: $M = ho V = ho \left( \frac{4}{3} \pi R^3 ight)$.Substituting this into the expression for $g$:$g = \frac{G}{R^2} 	imes \left( \frac{4}{3} \pi R^3 ho ight) = \frac{4}{3} \pi G R ho$.Since $G$,$\pi$,and $ho$ are constants for both planets,we find that $g \propto R$.Therefore,the acceleration due to gravity is directly proportional to the radius of the planet. Thus,it would be greater on the larger planet.

Two planets have the same density but different radii. The acceleration due to gravity would be ........

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