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(C) The resultant amplitude $A$ of two waves with amplitudes $A_1$ and $A_2$ and phase difference $\phi$ is given by the formula: $A = \sqrt{A_1^2 + A

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$1.73 E_0$

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(C) The resultant amplitude $A$ of two waves with amplitudes $A_1$ and $A_2$ and phase difference $\phi$ is given by the formula: $A = \sqrt{A_1^2 + A_2^2 + 2A_1 A_2 \cos \phi}$.Here,$A_1 = E_0$,$A_2 = E_0$,and $\phi = \frac{\pi}{3}$.Substituting these values into the formula:$A = \sqrt{E_0^2 + E_0^2 + 2(E_0)(E_0) \cos(\frac{\pi}{3})}$Since $\cos(\frac{\pi}{3}) = 0.5$,we have:$A = \sqrt{E_0^2 + E_0^2 + 2E_0^2(0.5)}$$A = \sqrt{2E_0^2 + E_0^2} = \sqrt{3E_0^2}$$A = \sqrt{3} E_0 \approx 1.732 E_0$.

Two plane polarized light waves combine at a certain point whose electric field components are $E_1 = E_0 \sin(\omega t)$ and $E_2 = E_0 \sin(\omega t + \frac{\pi}{3})$. Find the amplitude of the resultant wave.

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