What is the path difference for destructive i | vedclass

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(D) For destructive interference,the waves must arrive at the point out of phase by an odd multiple of $\pi$ radians.This corresponds to a path differ

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$\frac{(2n + 1)\lambda}{2}$

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(D) For destructive interference,the waves must arrive at the point out of phase by an odd multiple of $\pi$ radians.This corresponds to a path difference that is an odd multiple of half the wavelength $(\frac{\lambda}{2})$.Mathematically,the path difference $\Delta x$ is given by $\Delta x = (2n + 1) \frac{\lambda}{2}$,where $n = 0, 1, 2, 3, \dots$.Therefore,the correct option is $(d)$.

What is the path difference for destructive interference?

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