If the wavelength of light is 4000 mathring A | vedclass

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(C) The wavelength of light is given as $\lambda = 4000 \mathring A = 4000 	imes 10^{-10} \ m = 4 	imes 10^{-7} \ m$.The total length is $L = 1 \ mm

Vedclass · Accepted Answer

$0.25 	imes 10^4$

Vedclass · Answer

(C) The wavelength of light is given as $\lambda = 4000 \mathring A = 4000 	imes 10^{-10} \ m = 4 	imes 10^{-7} \ m$.The total length is $L = 1 \ mm = 10^{-3} \ m$.The number of waves $n$ is given by the ratio of the total length to the wavelength:$n = \frac{L}{\lambda} = \frac{10^{-3} \ m}{4 	imes 10^{-7} \ m}$.$n = \frac{1}{4} 	imes 10^{-3 - (-7)} = 0.25 	imes 10^4$.Therefore,the number of waves is $0.25 	imes 10^4$.

If the wavelength of light is $4000 \mathring A$,then the number of waves in $1 \ mm$ length will be

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