The velocity-time graph for a particle moving along $x$-axis is shown in the figure. The corresponding displacement-time graph is correctly shown by
- A
- B
- C
- D
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The acceleration of a train between two stations is shown in the figure. The maximum speed of the train is $............\,m/s$
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The acceleration time graph of a particle moving along a straight line is shown. At what time particle acquires its initial velocity........$s$
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Give important factor to control the speed of vehicle in area of school or hospital.
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Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
Colum $I$
Colum $II$
$(A)$ Velocity-time graph
$(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph
$(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph
$(r)$ Slope $\rightarrow$ zero
$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
$(u)$ |Slope| $\rightarrow$ constant
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
| Colum $I$ | Colum $II$ |
| $(A)$ Velocity-time graph | $(p)$ Slope $\rightarrow$ negative |
| $(B)$ Acceleration-time graph | $(q)$ Slope $\rightarrow$ positive |
| $(C)$ Displacement-time graph | $(r)$ Slope $\rightarrow$ zero |
| $(s)$ $\mid$ Slope $\mid \rightarrow$ increasing | |
| $(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing | |
| $(u)$ |Slope| $\rightarrow$ constant |
The relation between time ' $t$ ' and distance ' $x$ ' is $t=$ $\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. The relation between acceleration $(a)$ and velocity $(v)$ is:
The relation between time ' $t$ ' and distance ' $x$ ' is $t=$ $\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. The relation between acceleration $(a)$ and velocity $(v)$ is:
- [JEE MAIN 2024]