(C) The pure solvent has a higher vapour pressure than the solution containing a non-volatile solute. In the sealed container,the solvent molecules ev

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The volume of the solution increases and the volume of the solvent decreases.

(C) The pure solvent has a higher vapour pressure than the solution containing a non-volatile solute. In the sealed container,the solvent molecules evaporate from the pure solvent beaker to establish equilibrium. Since the solution has a lower vapour pressure,the solvent vapour condenses into the solution beaker to maintain the equilibrium vapour pressure. Consequently,the volume of the pure solvent decreases while the volume of the solution increases.

Class 12 Chemistry Solutions Lowering of vapour pressure

Two open beakers,one containing a solvent and the other containing a mixture of that solvent with a non-volatile solute,are together sealed in a container. Over time:

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A
The volume of the solution does not change and the volume of the solvent decreases.
B
The volume of the solution decreases and the volume of the solvent decreases.
C
The volume of the solution increases and the volume of the solvent decreases.
D
The volume of the solution and the solvent does not change.

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At $20^{\circ} C$,the vapour pressure of benzene is $70 \, torr$ and that of methyl benzene is $20 \, torr$. The mole fraction of benzene in the vapor phase at $20^{\circ} C$ above an equimolar mixture of benzene and methyl benzene is $..... \times 10^{-2}$ (Nearest integer).

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When a solid solute is dissolved in a volatile solvent to form a solution,then .......

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Calculate the vapour pressure of pure volatile liquid $A$ at a given temperature if the mole fraction and vapour pressure of pure volatile liquid $B$ are $0.4$ and $900 \ mm \ Hg$ respectively,given that the total vapour pressure of the solution is $600 \ mm \ Hg$. (in $mm \ Hg$)

MediumMHT CET 2025

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The mass of glucose that should be dissolved in $100 \ g$ of water in order to produce the same relative lowering of vapour pressure as is produced by dissolving $1 \ g$ of urea (molar mass $= 60 \ g/mol$) in $50 \ g$ of water is ........... $g$. (Assume dilute solution in both cases):-

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Calculate the weight of non-volatile solute having molecular weight $40$,which is dissolved in $57 \ g$ octane to reduce its vapour pressure by $20\%$.

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Two open beakers,one containing a solvent and the other containing a mixture of that solvent with a non-volatile solute,are together sealed in a container. Over time:

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At $20^{\circ} C$,the vapour pressure of benzene is $70 \, torr$ and that of methyl benzene is $20 \, torr$. The mole fraction of benzene in the vapor phase at $20^{\circ} C$ above an equimolar mixture of benzene and methyl benzene is $..... \times 10^{-2}$ (Nearest integer).

When a solid solute is dissolved in a volatile solvent to form a solution,then .......

Calculate the vapour pressure of pure volatile liquid $A$ at a given temperature if the mole fraction and vapour pressure of pure volatile liquid $B$ are $0.4$ and $900 \ mm \ Hg$ respectively,given that the total vapour pressure of the solution is $600 \ mm \ Hg$. (in $mm \ Hg$)

The mass of glucose that should be dissolved in $100 \ g$ of water in order to produce the same relative lowering of vapour pressure as is produced by dissolving $1 \ g$ of urea (molar mass $= 60 \ g/mol$) in $50 \ g$ of water is ........... $g$. (Assume dilute solution in both cases):-

Calculate the weight of non-volatile solute having molecular weight $40$,which is dissolved in $57 \ g$ octane to reduce its vapour pressure by $20\%$.

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