Two monoatomic ideal gases A and B of molecul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The speed of sound in a gaseous medium is given by the formula $v = \sqrt{\frac{\gamma R T}{M}}$,where $\gamma$ is the adiabatic index (ratio of s

Vedclass · Accepted Answer

$\sqrt{\frac{m_2}{m_1}}$

Vedclass · Answer

(A) The speed of sound in a gaseous medium is given by the formula $v = \sqrt{\frac{\gamma R T}{M}}$,where $\gamma$ is the adiabatic index (ratio of specific heats $C_P/C_V$),$R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molecular mass of the gas.Since both gases are monoatomic,the value of $\gamma$ is the same for both $(\gamma = 5/3)$.Given that both gases are at the same temperature $T$,the variables $\gamma, R,$ and $T$ are constant for both gases.Therefore,the speed of sound is inversely proportional to the square root of the molecular mass: $v \propto \frac{1}{\sqrt{M}}$.The ratio of the speed of sound in gas $A$ $(v_1)$ to that in gas $B$ $(v_2)$ is given by: $\frac{v_1}{v_2} = \sqrt{\frac{m_2}{m_1}}$.

Two monoatomic ideal gases $A$ and $B$ of molecular masses $m_1$ and $m_2$ respectively,are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas $A$ to that in gas $B$ is given by

Similar Questions

The velocity of sound in a gas at pressure $P$ and density $d$ is

Which of the following waves is used in sonography?

$A$ metal rod of $1 \; m$ length is dropped vertically onto a hard metal floor. Using an oscilloscope,it is determined that the impact produces a longitudinal wave of $1.2 \; kHz$ frequency. The speed of sound in the metal rod is: (in $; m/s$)

Find the wavelength of a sound wave of frequency $4.2 \text{ MHz}$ travelling with a speed of $1.7 \text{ km/s}$.

The velocity of sound in air is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module