(D) Given: $r_1 = 1\,cm$,$r_2 = 2\,cm$,$Q_1 = 10^{-2}\,C$,$Q_2 = 5 \times 10^{-2}\,C$.When two spheres are connected by a conducting wire,charge flows

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(D) Given: $r_1 = 1\,cm$,$r_2 = 2\,cm$,$Q_1 = 10^{-2}\,C$,$Q_2 = 5 \times 10^{-2}\,C$.When two spheres are connected by a conducting wire,charge flows until both reach the same potential.The total charge $Q_{total} = Q_1 + Q_2 = 10^{-2} + 5 \times 10^{-2} = 6 \times 10^{-2}\,C$.The final charge on the smaller sphere $(Q'_1)$ is given by the formula $Q'_1 = Q_{total} \times \frac{r_1}{r_1 + r_2}$.Substituting the values: $Q'_1 = (6 \times 10^{-2}) \times \frac{1}{1 + 2} = (6 \times 10^{-2}) \times \frac{1}{3} = 2 \times 10^{-2}\,C$.

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

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Two metallic spheres of radii $1\,cm$ and $2\,cm$ are given charges $10^{-2}\,C$ and $5 \times 10^{-2}\,C$ respectively. If they are connected by a conducting wire,the final charge on the smaller sphere is

AIPMT 1995 All AIPMT

A
$3 \times 10^{-2}\,C$
B
$1 \times 10^{-2}\,C$
C
$4 \times 10^{-2}\,C$
D
$2 \times 10^{-2}\,C$

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

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Two metallic spheres of radii $1\,cm$ and $2\,cm$ are given charges $10^{-2}\,C$ and $5 \times 10^{-2}\,C$ respectively. If they are connected by a conducting wire,the final charge on the smaller sphere is

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