Two long capillary tubes A and B of radius R_ | vedclass

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(A) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$,where $T$ is surface tension,$

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Water rise is more in $A$ than $B$.

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(A) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$,where $T$ is surface tension,$	heta$ is the contact angle,$r$ is the radius of the tube,$ho$ is the density of the liquid,and $g$ is the acceleration due to gravity.Since $T, 	heta, ho,$ and $g$ are constant for the same liquid and the same material of the tube,we have $h \propto \frac{1}{r}$.Given that $R_B > R_A$,it follows that $\frac{1}{R_A} > \frac{1}{R_B}$.Therefore,the height of the liquid rise $h_A$ in tube $A$ will be greater than the height $h_B$ in tube $B$ $(h_A > h_B)$.

Two long capillary tubes $A$ and $B$ of radius $R_B > R_A$ are dipped in the same liquid. Then:

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