Two identical thin bar magnets each of length | vedclass

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(C) Each magnet has a magnetic moment vector $\vec{M_1}$ and $\vec{M_2}$ with magnitude $M = ml$.Since the magnets are placed at right angles to each

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$\sqrt{2} ml$

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(C) Each magnet has a magnetic moment vector $\vec{M_1}$ and $\vec{M_2}$ with magnitude $M = ml$.Since the magnets are placed at right angles to each other,the angle between their magnetic moment vectors is $90^{\circ}$.The resultant magnetic moment of the system is given by the vector sum $\vec{M_{net}} = \vec{M_1} + \vec{M_2}$.The magnitude of the resultant magnetic moment is $M_{net} = \sqrt{M_1^2 + M_2^2 + 2M_1M_2 \cos(90^{\circ})}$.Since $\cos(90^{\circ}) = 0$,we have $M_{net} = \sqrt{M^2 + M^2} = \sqrt{2M^2} = \sqrt{2}M$.Substituting $M = ml$,we get $M_{net} = \sqrt{2} ml$.

Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is:

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