$A$ magnetized steel wire of length $L$ has a magnetic moment $M$. It is then bent into a semicircular arc. The new magnetic moment is:

$A$ rod of length $5 \, cm$ and diameter $1 \, cm$ has a magnetization of $5.30 \times 10^3 \, A/m$. What is its magnetic moment?

$A$ bar magnet $AB$ is cut into two equal parts as shown in the figure. One part is kept over the other so that the pole $C_{2}$ is above $C_{1}$. If $M$ is the magnetic moment of the original magnet,the magnetic moment of the combination so formed is

$A$ sample of a ferromagnetic iron in the shape of a cube of side $1.0 \mu m$ contains $8.7 \times 10^{28}$ atoms per cubic metre and the magnetic dipole moment of each iron atom is $9.3 \times 10^{-24} A m^2$. Then the maximum possible magnetic dipole moment (in $A m^2$) of the sample is nearly

$A$ bar magnet of magnetic moment $M$ is cut into two parts of equal length. The magnetic moment of each part will be ......... $M$.

Magnetic lines of force due to a bar magnet do not intersect because