Two identical charged spheres are suspended b | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

From $\mathrm{FBD}$ of sphere, using theorem,

$\frac{\mathrm{F}}{\mathrm{mg}}=	an 	heta$           ..........$(i)$

Vedclass · Accepted Answer

$4$

Vedclass · Answer

From $\mathrm{FBD}$ of sphere, using theorem,

$\frac{\mathrm{F}}{\mathrm{mg}}=	an 	heta$           ..........$(i)$

when suspended in liquid, as $	heta$ remains same,

$\frac{\mathrm{F}^{\prime}}{\operatorname{mg}\left(1-\frac{ho}{\mathrm{d}}ight)}=	an 	heta$           .........$(ii)$

Using eqns. $(i)$ and $(ii),$

$\frac{\mathrm{F}}{\mathrm{mg}}=\frac{\mathrm{F}^{\prime}}{\mathrm{mg}\left(1-\frac{ho}{\mathrm{d}}ight)}$

where, $\quad \mathrm{F}^{\prime}=\frac{\mathrm{F}}{\mathrm{K}}$

$	herefore \frac{\mathrm{F}}{\mathrm{mg}}=\frac{\mathrm{F}^{\prime}}{\operatorname{mg} \mathrm{K}\left(1-\frac{ho}{\mathrm{d}}ight)}$

or $\quad \mathrm{K}=\frac{1}{1-\frac{ho}{\mathrm{d}}}=2$

Similar Questions

If two charges of $1$ coulomb each are placed $1 \,km$ apart, then the force between them will be ........... $N$

A total charge $Q$ is broken in two parts ${Q_1}$ and ${Q_2}$ and they are placed at a distance $R$ from each other. The maximum force of repulsion between them will occur, when

Two charges $q$ and $-3q$ are placed fixed on $x-axis$ separated by distance $'d'$. Where should a third charge $2q$ be placed such that it will not experience any force ?

Two fixed charges $4\,Q$ (positive) and $Q$ (negative) are located at $A$ and $B$, the distance $AB$ being $3$ $m$.

Force between $A$ and $B$ is $F$. If $75\%$ charge of $A$ is transferred to $B$ then force between $A$ and $B$ is