Two flasks A and B have equal volumes. A is m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total kinetic energy $(K.E.)$ of an ideal gas is given by the formula: $K.E. = \frac{3}{2} nRT$. For flask $A$ containing $H_2$: $n_A = \frac{

Vedclass · Accepted Answer

$11:1$

Vedclass · Answer

(B) The total kinetic energy $(K.E.)$ of an ideal gas is given by the formula: $K.E. = \frac{3}{2} nRT$. For flask $A$ containing $H_2$: $n_A = \frac{m}{M_{H_2}} = \frac{m}{2}$ and $T_A = 300 \ K$. Thus,$(K.E.)_A = \frac{3}{2} 	imes \frac{m}{2} 	imes R 	imes 300$. For flask $B$ containing $CO_2$: $n_B = \frac{m}{M_{CO_2}} = \frac{m}{44}$ and $T_B = 600 \ K$. Thus,$(K.E.)_B = \frac{3}{2} 	imes \frac{m}{44} 	imes R 	imes 600$. Taking the ratio: $\frac{(K.E.)_A}{(K.E.)_B} = \frac{\frac{m}{2} 	imes 300}{\frac{m}{44} 	imes 600} = \frac{300/2}{600/44} = \frac{150}{600/44} = \frac{150 	imes 44}{600} = \frac{44}{4} = 11:1$.

Two flasks $A$ and $B$ have equal volumes. $A$ is maintained at $300 \ K$ and $B$ at $600 \ K$. Equal masses of $H_2$ and $CO_2$ are taken in flasks $A$ and $B$ respectively. Find the ratio of total $K.E.$ of gases in flask $A$ to that of $B$.

Similar Questions

Which of the following gas mixtures is not applicable for Dalton's law of partial pressure?

Which one of the following equations represents the variation of viscosity coefficient $(\eta)$ with temperature $(T)$?

Which one of the following statements is not correct?

Consider the following statements:
$Statement-I$ : If the intermolecular forces are stronger than thermal energy,the substance prefers to be in a gaseous state.
$Statement-II$ : Among all elements,the total number of elements available as gases at room temperature is $10$.

At the same temperature and pressure,the rate of diffusion of helium with respect to methane is ...... .

Vedclass Test Series

Exam Paper Generator

Online Exam Module