Two electric dipoles of dipole moments 1.2 ti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The maximum torque experienced by an electric dipole in a uniform electric field is given by the formula $|	au|_{\max} = PE$,where $P$ is the dip

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The maximum torque experienced by an electric dipole in a uniform electric field is given by the formula $|	au|_{\max} = PE$,where $P$ is the dipole moment and $E$ is the electric field strength.For the first dipole: $P_1 = 1.2 	imes 10^{-30} \, C \cdot m$ and $E_1 = 5 	imes 10^{4} \, N \cdot C^{-1}$.For the second dipole: $P_2 = 2.4 	imes 10^{-30} \, C \cdot m$ and $E_2 = 15 	imes 10^{4} \, N \cdot C^{-1}$.The ratio of the maximum torques is given by:$\frac{	au_1}{	au_2} = \frac{P_1 E_1}{P_2 E_2} = \frac{(1.2 	imes 10^{-30}) 	imes (5 	imes 10^{4})}{(2.4 	imes 10^{-30}) 	imes (15 	imes 10^{4})}$Simplifying the expression:$\frac{	au_1}{	au_2} = \left(\frac{1.2}{2.4}ight) 	imes \left(\frac{5}{15}ight) = \left(\frac{1}{2}ight) 	imes \left(\frac{1}{3}ight) = \frac{1}{6}$Comparing this to $\frac{1}{x}$,we find that $x = 6$.

Similar Questions

Assertion $:-$ An electric dipole experiences maximum force in a uniform electric field,when it is placed with its axis at right angles to the field direction.
Reason $:-$ When the axis of a dipole is perpendicular to a uniform external electric field,then torque acting on it will be zero.

Two charges $+q$ and $-q$ are kept at a certain distance apart. Then, at any point on the perpendicular bisector of the line joining the two charges:

Two point dipoles of dipole moments $\vec{p}_1$ and $\vec{p}_2$ are at a distance $x$ from each other,and $\vec{p}_1 \parallel \vec{p}_2$. The force between the dipoles is:

An electric dipole of length $20 \ cm$ having $\pm 3 \times 10^{-3} \ C$ charge is placed at $60^{\circ}$ with respect to a uniform electric field and experiences a torque of magnitude $6 \ N-m$. The potential energy of the dipole is:

An electric dipole of dipole moment $p$ is aligned parallel to a uniform electric field $E$. The energy required to rotate the dipole by $90^{\circ}$ is $\left[\begin{array}{ll}\sin 0^{\circ}=0, & \sin 90^{\circ}=1 \\ \cos 0^{\circ}=1, & \cos 90^{\circ}=0\end{array}\right]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module