Two charges +q and -q are kept at a certain d | vedclass

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Question

(B) The perpendicular bisector of the line joining two equal and opposite charges ($+q$ and $-q$) is known as the equatorial line of the electric dipo

Vedclass · Accepted Answer

the electric potential is zero

Vedclass · Answer

(B) The perpendicular bisector of the line joining two equal and opposite charges ($+q$ and $-q$) is known as the equatorial line of the electric dipole.
For any point on the equatorial line at a distance $r$ from the center of the dipole, the electric potential $V$ is given by the sum of potentials due to individual charges:
$V = \frac{1}{4 \pi \varepsilon_0} \left( \frac{q}{r_1} + \frac{-q}{r_2} \right)$
Since any point on the perpendicular bisector is equidistant from both charges, $r_1 = r_2$, which implies $V = 0$.
However, the electric field strength $E$ at this point is not zero. It is directed parallel to the dipole axis (from $+q$ to $-q$) and is given by $E = \frac{1}{4 \pi \varepsilon_0} \frac{p}{r^3}$ (for $r \gg a$).

Two charges $+q$ and $-q$ are kept at a certain distance apart. Then, at any point on the perpendicular bisector of the line joining the two charges:

Similar Questions

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