Two different loops are concentric and lie in the same plane. The current in the outer loop is clockwise and increasing with time. The induced current in the inner loop then,is

$A$ circular loop of radius $7 \ cm$ is placed in a uniform magnetic field of $0.2 \ T$ directed perpendicular to the plane of the loop. The loop is converted into a square loop in $0.5 \ s$. The $EMF$ induced in the loop is . . . . . . $mV$.

Shown in the figure is a circular loop of radius $r$ and resistance $R$. $A$ variable magnetic field of induction $B = B_0 e^{-t}$ is established inside the coil. If the key $(K)$ is closed,the electrical power developed right after closing the switch is equal to

$A$ $10 \Omega$ coil of $180$ turns and diameter $4 \text{ cm}$ is placed in a uniform magnetic field so that the magnetic flux is maximum through the coil's cross-sectional area. When the field is suddenly removed, a charge of $360 \mu \text{C}$ flows through a $618 \Omega$ galvanometer connected to the coil. Find the magnetic field. (in $\text{ T}$)

$A$ coil of $n$ turns and area $A$ is suddenly removed from a magnetic field,and a charge $q$ flows through the coil. If the resistance of the coil is $R$,then the magnetic flux density is (in $Wb/m^2$):

Assertion: An $emf$ $\vec{E}$ is induced in a closed loop where magnetic flux is varied. The induced $\vec{E}$ is not a conservative field.
Reason: The line integral $\oint \vec{E} \cdot d\vec{l}$ around the closed loop is nonzero.