Assertion: An emf vec{E} is induced in a clos | vedclass

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(A) According to Faraday's law of electromagnetic induction,the induced $emf$ in a closed loop is given by $\oint \vec{E} \cdot d\vec{l} = -\frac{d\ph

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) According to Faraday's law of electromagnetic induction,the induced $emf$ in a closed loop is given by $\oint \vec{E} \cdot d\vec{l} = -\frac{d\phi}{dt}$.Since the magnetic flux $\phi$ is varying,the line integral $\oint \vec{E} \cdot d\vec{l}$ is non-zero.$A$ field is defined as conservative if the line integral of the field around any closed loop is zero. Since the line integral here is non-zero,the induced electric field $\vec{E}$ is a non-conservative field.Therefore,both the Assertion and the Reason are correct,and the Reason correctly explains the Assertion.

Assertion: An $emf$ $\vec{E}$ is induced in a closed loop where magnetic flux is varied. The induced $\vec{E}$ is not a conservative field.
Reason: The line integral $\oint \vec{E} \cdot d\vec{l}$ around the closed loop is nonzero.

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Assertion: An $emf$ $\vec{E}$ is induced in a closed loop where magnetic flux is varied. The induced $\vec{E}$ is not a conservative field.Reason: The line integral $\oint \vec{E} \cdot d\vec{l}$ around the closed loop is nonzero.