Two different coils have self-inductance $L_1 = 8 \, mH$ and $L_2 = 2 \, mH$. The current in both coils is increased at the same constant rate. At a certain instant of time,the power supplied to the two coils is the same. At that time,the current,induced voltage,and energy stored in the first coil are $i_1, V_1$,and $W_1$ respectively. Corresponding values for the second coil at the same instant are $i_2, V_2$,and $W_2$ respectively. Then:
- A$\frac{i_1}{i_2} = \frac{1}{4}$
- B$\frac{V_2}{V_1} = \frac{1}{4}$
- C$\frac{W_2}{W_1} = 4$
- DAll of the above
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View SolutionAssertion: $A$ current continues to flow in a superconducting coil even after the switch is off.
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Reason: Superconducting coils show the Meissner effect.
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