Two dice are rolled. If both dice have six faces numbered $1, 2, 3, 5, 7,$ and $11,$ then the probability that the sum of the numbers on the top faces is less than or equal to $8$ is

  • A
    $\frac{4}{9}$
  • B
    $\frac{17}{36}$
  • C
    $\frac{5}{12}$
  • D
    $\frac{1}{2}$

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