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Question

(B) The total number of possible outcomes when two dice are thrown is $6 	imes 6 = 36$.The product of two numbers is odd only if both numbers are odd

Vedclass · Accepted Answer

$\frac{3}{4}$

Vedclass · Answer

(B) The total number of possible outcomes when two dice are thrown is $6 	imes 6 = 36$.The product of two numbers is odd only if both numbers are odd. The odd numbers on a die are ${1, 3, 5}$.The number of outcomes where both numbers are odd is $3 	imes 3 = 9$.The product is even if it is not odd. Therefore,the number of favourable outcomes where the product is even is $36 - 9 = 27$.The probability $P(E)$ is given by $\frac{	ext{Number of favourable outcomes}}{	ext{Total number of outcomes}} = \frac{27}{36} = \frac{3}{4}$.

Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

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