4 coins are tossed once. Find the probability | vedclass

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(B) When $4$ coins are tossed, the total number of possible outcomes is $2^4 = 16$.The event 'at least $1$ tail' is the complement of the event 'no ta

Vedclass · Accepted Answer

$\frac{15}{16}$

Vedclass · Answer

(B) When $4$ coins are tossed, the total number of possible outcomes is $2^4 = 16$.The event 'at least $1$ tail' is the complement of the event 'no tails' (i.e., all heads).The only outcome with no tails is $(H, H, H, H)$, so there is only $1$ such outcome.$P(	ext{all heads}) = \frac{1}{16}$.$P(	ext{at least } 1 	ext{ tail}) = 1 - P(	ext{all heads})$.$P(	ext{at least } 1 	ext{ tail}) = 1 - \frac{1}{16} = \frac{15}{16}$.

$4$ coins are tossed once. Find the probability of getting at least $1$ tail.

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