Two cylindrical vessels A and B of different | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The pressure at the bottom of a vessel containing a liquid of density $\rho$ at a height $h$ is given by the formula $P = P_0 + \rho gh$,where $P_

Vedclass · Accepted Answer

$1: 1$

Vedclass · Answer

(A) The pressure at the bottom of a vessel containing a liquid of density $\rho$ at a height $h$ is given by the formula $P = P_0 + \rho gh$,where $P_0$ is the atmospheric pressure.Since both vessels are filled with water (same density $\rho$) to the same height $h$,and are kept on the same horizontal plane (same atmospheric pressure $P_0$),the pressure at the bottom of both vessels depends only on the height $h$ and density $\rho$.Therefore,the pressure at the bottom of vessel $A$ is $P_A = P_0 + \rho gh$ and the pressure at the bottom of vessel $B$ is $P_B = P_0 + \rho gh$.Thus,$P_A = P_B$.The ratio of the pressures at the bottom of the vessels $A$ and $B$ is $P_A : P_B = 1 : 1$.

Similar Questions

Select the wrong statement about pressure.

$A$ cylindrical vessel of base radius $R$ and height $H$ has a narrow neck of height $h$ and radius $r$ at one end (see figure). The vessel is filled with water (density $\rho_w$) and its neck is filled with immiscible oil (density $\rho_0$). Then,the pressure at

Three identical vessels are filled with three liquids $A, B$,and $C$ with equal masses but having densities $\rho_A, \rho_B$,and $\rho_C$ respectively. If $\rho_A > \rho_B > \rho_C$,then the pressure at the bottom of the vessels will be:

The relative density of Kerosene is $0.8$. Find its density. (in $kg/m^3$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module