Two condensers of capacity 0.3,mu F and 0.6,m | vedclass

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(B) In a series combination,the charge $Q$ on each capacitor is the same.Energy stored in a capacitor is given by the formula $U = \frac{Q^2}{2C}$.Sin

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$2$

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(B) In a series combination,the charge $Q$ on each capacitor is the same.Energy stored in a capacitor is given by the formula $U = \frac{Q^2}{2C}$.Since $Q$ is constant,the energy $U$ is inversely proportional to the capacitance $C$,i.e.,$U \propto \frac{1}{C}$.Therefore,the ratio of energies stored is $\frac{U_1}{U_2} = \frac{C_2}{C_1}$.Given $C_1 = 0.3\,\mu F$ and $C_2 = 0.6\,\mu F$,we have $\frac{U_1}{U_2} = \frac{0.6}{0.3} = 2$.Thus,the ratio is $2:1$ or $2$.

Two condensers of capacity $0.3\,\mu F$ and $0.6\,\mu F$ respectively are connected in series. The combination is connected across a potential of $6\,V$. The ratio of energies stored by the condensers will be

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