A 700,pF capacitor is charged by a 50,V batte | vedclass

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Question

(D) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2}CV^2$.Given:Capacitance $C = 700\,pF = 700 	imes 10^{-12}\,F = 7 	i

Vedclass · Accepted Answer

$8.75 	imes 10^{-7}\,J$

Vedclass · Answer

(D) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2}CV^2$.Given:Capacitance $C = 700\,pF = 700 	imes 10^{-12}\,F = 7 	imes 10^{-10}\,F$.Potential difference $V = 50\,V$.Substituting the values:$U = \frac{1}{2} 	imes (700 	imes 10^{-12}) 	imes (50)^2$$U = \frac{1}{2} 	imes 700 	imes 10^{-12} 	imes 2500$$U = 350 	imes 2500 	imes 10^{-12}$$U = 875000 	imes 10^{-12}\,J$$U = 8.75 	imes 10^{-7}\,J$.

$A$ $700\,pF$ capacitor is charged by a $50\,V$ battery. The electrostatic energy stored by it is

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