Two capacitors,one of capacity $C$ and other of capacity $C/2$ are connected to a $V$ volt battery,as shown in the figure. The work done in charging fully both the capacitors is

$A$ fully charged capacitor with capacitance $C$ is discharged through a small resistance coil embedded in a thermally insulated block of mass $m$ and specific heat $s$. If the temperature of the block increases by $\Delta T$,then the potential difference across the capacitor is:

$A$ parallel plate capacitor has a potential of $20 \, kV$ and a capacitance of $2 \times 10^{-4} \, \mu F$. If the area of the plates is $0.01 \, m^2$ and the distance between the plates is $2 \, mm$,find the energy stored in the capacitor.

In the figure,the charge on the capacitor is plotted against the potential difference across the capacitor. The capacitance and energy stored in the capacitor are respectively:

If a $12 \ pF$ capacitor is connected to a $50 \ V$ battery,then the electrostatic energy stored in the capacitor is . . . . . . .

An air-filled parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A$,the energy stored in the capacitor is ($\epsilon_{0} =$ permittivity of free space).