Two coins are tossed simultaneously $400$ times with the following frequencies of different outcomes:
Two heads: $100$ times
One head: $220$ times
No head: $80$ times
Find the probability of occurrence of each of these events.
Two heads: $100$ times
One head: $220$ times
No head: $80$ times
Find the probability of occurrence of each of these events.
(N/A) The total number of trials is $400$.
$1$. Probability of getting two heads = (Number of times two heads occurred) / (Total number of trials) = $100 / 400 = 0.25$.
$2$. Probability of getting one head = (Number of times one head occurred) / (Total number of trials) = $220 / 400 = 0.55$.
$3$. Probability of getting no head = (Number of times no head occurred) / (Total number of trials) = $80 / 400 = 0.20$.
$1$. Probability of getting two heads = (Number of times two heads occurred) / (Total number of trials) = $100 / 400 = 0.25$.
$2$. Probability of getting one head = (Number of times one head occurred) / (Total number of trials) = $220 / 400 = 0.55$.
$3$. Probability of getting no head = (Number of times no head occurred) / (Total number of trials) = $80 / 400 = 0.20$.
Explore More
Similar Questions
$A$ die is thrown $400$ times with the frequencies for the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:
Outcome $1$ $2$ $3$ $4$ $5$ $6$ Frequency $68$ $70$ $74$ $54$ $70$ $64$
Find the probability of getting each outcome.
| Outcome | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| Frequency | $68$ | $70$ | $74$ | $54$ | $70$ | $64$ |
Find the probability of getting each outcome.
Medium
View Solution$A$ company selected $4000$ households at random and surveyed them to find out a relationship between income level and the number of television sets in a home. The information obtained is listed in the following table:
Monthly income (in Rs) Number of Televisions per household $0, 1, 2, \text{Above } 2$ $< 10000$ $20, 80, 10, 0$ $10000-14999$ $10, 240, 60, 0$ $15000-19999$ $0, 380, 120, 30$ $20000-24999$ $0, 520, 370, 80$ $25000$ and above $0, 1100, 760, 220$
Find the probability of a household not having any television.
| Monthly income (in Rs) | Number of Televisions per household |
| $0, 1, 2, \text{Above } 2$ | |
| $< 10000$ | $20, 80, 10, 0$ |
| $10000-14999$ | $10, 240, 60, 0$ |
| $15000-19999$ | $0, 380, 120, 30$ |
| $20000-24999$ | $0, 520, 370, 80$ |
| $25000$ and above | $0, 1100, 760, 220$ |
Find the probability of a household not having any television.
Easy
View SolutionThe probability of an event of a mango growing on an acacia tree is ..........
Easy
View SolutionThe probability of a certain event is ........
Easy
View SolutionHere is an extract from a mortality table.
Age (in years) Number of persons surviving out of a sample of one million $60$ $16090$ $61$ $11490$ $62$ $8012$ $63$ $5448$ $64$ $3607$ $65$ $2320$
Based on this information,what is the probability of a person aged $60$ dying within a year?
| Age (in years) | Number of persons surviving out of a sample of one million |
| $60$ | $16090$ |
| $61$ | $11490$ |
| $62$ | $8012$ |
| $63$ | $5448$ |
| $64$ | $3607$ |
| $65$ | $2320$ |
Based on this information,what is the probability of a person aged $60$ dying within a year?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo