$A$ company selected $4000$ households at random and surveyed them to find out a relationship between income level and the number of television sets in a home. The information obtained is listed in the following table:
Monthly income (in Rs) Number of Televisions per household $0, 1, 2, \text{Above } 2$ $< 10000$ $20, 80, 10, 0$ $10000-14999$ $10, 240, 60, 0$ $15000-19999$ $0, 380, 120, 30$ $20000-24999$ $0, 520, 370, 80$ $25000$ and above $0, 1100, 760, 220$
Find the probability of a household not having any television.
| Monthly income (in Rs) | Number of Televisions per household |
| $0, 1, 2, \text{Above } 2$ | |
| $< 10000$ | $20, 80, 10, 0$ |
| $10000-14999$ | $10, 240, 60, 0$ |
| $15000-19999$ | $0, 380, 120, 30$ |
| $20000-24999$ | $0, 520, 370, 80$ |
| $25000$ and above | $0, 1100, 760, 220$ |
Find the probability of a household not having any television.
- A$\frac{35}{1600}$
- B$\frac{30}{400}$
- C$\frac{3}{400}$
- D$\frac{3}{4000}$
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$A$ recent survey found that the ages of workers in a factory is distributed as follows:
Age (in years) $20-29$ $30-39$ $40-49$ $50-59$ $60$ and above Number of workers $38$ $27$ $86$ $46$ $3$
If a person is selected at random,find the probability that the person is under $60$ but over $39$ years.
| Age (in years) | $20-29$ | $30-39$ | $40-49$ | $50-59$ | $60$ and above |
| Number of workers | $38$ | $27$ | $86$ | $46$ | $3$ |
If a person is selected at random,find the probability that the person is under $60$ but over $39$ years.
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View SolutionTwo dice are thrown simultaneously $500$ times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:
Sum Frequency $2$ $14$ $3$ $30$ $4$ $42$ $5$ $55$ $6$ $72$ $7$ $75$ $8$ $70$ $9$ $53$ $10$ $46$ $11$ $28$ $12$ $15$
If the dice are thrown once more,what is the probability of getting a sum between $8$ and $12\,?$
| Sum | Frequency |
| $2$ | $14$ |
| $3$ | $30$ |
| $4$ | $42$ |
| $5$ | $55$ |
| $6$ | $72$ |
| $7$ | $75$ |
| $8$ | $70$ |
| $9$ | $53$ |
| $10$ | $46$ |
| $11$ | $28$ |
| $12$ | $15$ |
If the dice are thrown once more,what is the probability of getting a sum between $8$ and $12\,?$
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View SolutionOver the past $200$ working days,the number of defective parts produced by a machine is given in the following table:
Number of defective parts $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$ $9$ $10$ $11$ $12$ $13$ Days $50$ $32$ $22$ $18$ $12$ $12$ $10$ $10$ $10$ $8$ $6$ $6$ $2$ $2$
Determine the probability that tomorrow's output will have at least one defective part.
| Number of defective parts | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ | $8$ | $9$ | $10$ | $11$ | $12$ | $13$ |
| Days | $50$ | $32$ | $22$ | $18$ | $12$ | $12$ | $10$ | $10$ | $10$ | $8$ | $6$ | $6$ | $2$ | $2$ |
Determine the probability that tomorrow's output will have at least one defective part.
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View SolutionTwo dice are thrown simultaneously $500$ times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:
Sum Frequency $2$ $14$ $3$ $30$ $4$ $42$ $5$ $55$ $6$ $72$ $7$ $75$ $8$ $70$ $9$ $53$ $10$ $46$ $11$ $28$ $12$ $15$
If the dice are thrown once more,what is the probability of getting a sum more than $10\,?$
| Sum | Frequency |
| $2$ | $14$ |
| $3$ | $30$ |
| $4$ | $42$ |
| $5$ | $55$ |
| $6$ | $72$ |
| $7$ | $75$ |
| $8$ | $70$ |
| $9$ | $53$ |
| $10$ | $46$ |
| $11$ | $28$ |
| $12$ | $15$ |
If the dice are thrown once more,what is the probability of getting a sum more than $10\,?$
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