Two charges of 5 Q and -2 Q are situated at t | vedclass

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(B) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\varepsilon_0}$,wh

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$\frac{5 Q}{\varepsilon_0}$

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(B) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\varepsilon_0}$,where $q_{	ext{enclosed}}$ is the net charge enclosed by the surface.The sphere has a radius of $4 a$ and is centered at the origin $(0, 0)$.The charge $5 Q$ is located at $(3 a, 0)$. Since the distance from the origin is $3 a The charge $-2 Q$ is located at $(-5 a, 0)$. Since the distance from the origin is $5 a > 4 a$,this charge is outside the sphere.Therefore,the net charge enclosed by the sphere is $q_{	ext{enclosed}} = 5 Q$.Substituting this into Gauss's Law,we get $\phi = \frac{5 Q}{\varepsilon_0}$.

Two charges of $5 Q$ and $-2 Q$ are situated at the points $(3 a, 0)$ and $(-5 a, 0)$ respectively. The electric flux through a sphere of radius $4 a$ having its center at the origin is

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