Two charges ${q_1}$ and ${q_2}$ are placed in vacuum at a distance $d$ and the force acting between them is $F$. If a medium of dielectric constant $4$ is introduced around them, the force now will be
Two charges ${q_1}$ and ${q_2}$ are placed in vacuum at a distance $d$ and the force acting between them is $F$. If a medium of dielectric constant $4$ is introduced around them, the force now will be
- A
$4F$
- B
$2F$
- C
$\frac{F}{2}$
- D
$\frac{F}{4}$
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- [JEE MAIN 2023]
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- [JEE MAIN 2021]