A proton is projected with a velocity $10^7\, m/s$, at right angles to a uniform magnetic field of induction $100\, mT$. The time (in second) taken by the proton to traverse $90^o$ arc is  $(m_p = 1.65\times10^{-27}\, kg$ and $q_p = 1.6\times10^{-19}\, C)$

  • A

    $0.81\times10^{-7}$

  • B

    $1.62\times10^{-7}$

  • C

    $2.43\times10^{-7}$

  • D

    $3.24\times10^{-7}$

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