Two capillary tubes of different diameters are dipped in water. The rise of water is

Water rises up to height $x$ in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth $d$ in a mine,the water level rises up to height $Y$. If $R$ is the radius of the earth,then the ratio $Y:x$ is

Two long capillary tubes $A$ and $B$ of radius $R_B > R_A$ are dipped in the same liquid. Then:

$A$ capillary tube of radius '$r$' is immersed in water and water rises to a height of '$h$'. The mass of water in the capillary tube is $5 \times 10^{-3} \ kg$. The same capillary tube is now immersed in a liquid whose surface tension is $\sqrt{2}$ times the surface tension of water. The angle of contact between the capillary tube and this liquid is $45^{\circ}$. The mass of liquid which rises into the capillary tube now is (in $kg$):

In a capillary tube,water rises to $3\, mm$. The height of water that will rise in another capillary tube having one-third radius of the first is ........ $mm$.

$A$ vertical capillary tube is filled with water up to the top after closing its lower end with a finger. If the finger is removed,we shall observe that: ($T = 70 \,\, dyne/cm$,radius of capillary $r = 1 \,\, mm$ and $g = 980 \,\, cm/sec^2$)