Two capacitors of 10,mu F and 20,mu F are con | vedclass

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(D) In a series combination of capacitors,the charge on each capacitor is the same.Let the equivalent capacitance be $C_{eq}$. For two capacitors in s

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$200\,\mu C, 200\,\mu C$

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(D) In a series combination of capacitors,the charge on each capacitor is the same.Let the equivalent capacitance be $C_{eq}$. For two capacitors in series,$C_{eq} = \frac{C_1 C_2}{C_1 + C_2}$.Given $C_1 = 10\,\mu F$,$C_2 = 20\,\mu F$,and $V = 30\,V$.$C_{eq} = \frac{10 	imes 20}{10 + 20} = \frac{200}{30} = \frac{20}{3}\,\mu F$.The charge on each capacitor is $Q = C_{eq} 	imes V$.$Q = \left( \frac{20}{3}\,\mu F ight) 	imes 30\,V = 200\,\mu C$.Since they are in series,the charge on both capacitors is equal to $200\,\mu C$.

Two capacitors of $10\,\mu F$ and $20\,\mu F$ are connected in series with a $30\,V$ battery. The charge on the capacitors will be,respectively:

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