Four capacitors of equal capacitance have an equivalent capacitance $C_1$ when connected in series and an equivalent capacitance $C_2$ when connected in parallel. The ratio $\frac{C_1}{C_2}$ is:

  • A
    $1 / 4$
  • B
    $1 / 16$
  • C
    $1 / 8$
  • D
    $1 / 12$

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Find the equivalent capacitance between $A$ and $B$ of the following arrangement:

In the given circuit,a charge of $+80 \mu C$ is given to the upper plate of a $4 \mu F$ capacitor. At steady state,the charge on the upper plate of the $3 \mu F$ capacitor is (in $\mu C$)

The combination of capacitors with $C_1 = 3\,\mu F$,$C_2 = 4\,\mu F$,and $C_3 = 2\,\mu F$ is charged by connecting $A$ and $B$ to a battery. Consider the following statements:
$I.$ Energy stored in $C_1$ $=$ Energy stored in $C_2$ $+$ Energy stored in $C_3$
$II.$ Charge on $C_1$ $=$ Charge on $C_2$ $+$ Charge on $C_3$
$III.$ Potential drop across $C_1$ $=$ Potential drop across $C_2$ $=$ Potential drop across $C_3$
Which of these is/are correct?

The capacitors of capacity $C_1$ and $C_2$ are connected in parallel,then the equivalent capacitance is:

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