(A) For body $A$ starting from rest (initial velocity $u=0$): $S_A = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}at^2 = \frac{1}{2}at^2$ For body $B$ moving

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(A) For body $A$ starting from rest (initial velocity $u=0$): $S_A = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}at^2 = \frac{1}{2}at^2$ For body $B$ moving with uniform velocity $V$: $S_B = Vt$ Since they meet at the same point after time $t$,their displacements must be equal: $S_A = S_B$ $\frac{1}{2}at^2 = Vt$ Dividing both sides by $t$ (assuming $t \neq 0$): $\frac{1}{2}at = V$ $t = \frac{2V}{a}$

Class 11 Physics Motion in Straight Line Uniformly Accelerated Motion

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Two bodies $A$ and $B$ start from the same point at the same instant and move along a straight line. Body $A$ moves with uniform acceleration $a$ and body $B$ moves with uniform velocity $V$. They meet after time $t$. The value of $t$ is

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A
$\frac{2V}{a}$
B
$\frac{a}{2V}$
C
$\frac{V}{2a}$
D
$\sqrt{\frac{V}{a}}$

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Motion in Straight Line

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Uniformly Accelerated Motion

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If the displacement of a particle varies with time as $\sqrt{x} = t + 7$,then

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$A$ particle is moving along a straight line with constant acceleration. At the end of the $10^{th}$ second,its velocity becomes $20 \, m/s$,and in the $10^{th}$ second,it travels a distance of $10 \, m$. Then the acceleration of the particle will be ........ $m/s^2$.

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The relation between time $t$ and displacement $x$ is $t = \alpha x^2 + \beta x$,where $\alpha$ and $\beta$ are constants. If $v$ is the velocity,the retardation is:

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For a body moving with uniform acceleration along a straight line, the variation of its velocity $(v)$ with position $(x)$ is best represented by:

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$A$ goods train accelerating uniformly on a straight railway track approaches an electric pole standing on the side of the track. Its engine passes the pole with velocity $u$ and the guard's room passes with velocity $v$. The middle wagon of the train passes the pole with a velocity of:

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Two bodies $A$ and $B$ start from the same point at the same instant and move along a straight line. Body $A$ moves with uniform acceleration $a$ and body $B$ moves with uniform velocity $V$. They meet after time $t$. The value of $t$ is

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If the displacement of a particle varies with time as $\sqrt{x} = t + 7$,then

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