Two bodies A and B having masses in the ratio | vedclass

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(D) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since both bodies possess the same kinet

Vedclass · Accepted Answer

$\sqrt{3}:1$

Vedclass · Answer

(D) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since both bodies possess the same kinetic energy $(E_A = E_B = E)$,the ratio of their linear momenta is given by:$\frac{P_A}{P_B} = \frac{\sqrt{2m_A E}}{\sqrt{2m_B E}} = \sqrt{\frac{m_A}{m_B}}$.Given the ratio of masses is $\frac{m_A}{m_B} = \frac{3}{1}$,we substitute this into the equation:$\frac{P_A}{P_B} = \sqrt{\frac{3}{1}} = \sqrt{3} : 1$.Therefore,the correct option is $D$.

Two bodies $A$ and $B$ having masses in the ratio of $3 : 1$ possess the same kinetic energy. The ratio of their linear momenta is then

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