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(D) Given that the body is initially at rest,the initial velocity $u = 0$.According to Newton's second law,the acceleration $a = \frac{F}{m}$.Using th

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$\frac{F^{2} t^{2}}{2m}$

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(D) Given that the body is initially at rest,the initial velocity $u = 0$.According to Newton's second law,the acceleration $a = \frac{F}{m}$.Using the first equation of motion,the velocity $v$ at time $t$ is $v = u + at = 0 + \left(\frac{F}{m}\right)t = \frac{Ft}{m}$.The kinetic energy $K$ is given by the formula $K = \frac{1}{2}mv^{2}$.Substituting the value of $v$,we get $K = \frac{1}{2}m\left(\frac{Ft}{m}\right)^{2}$.$K = \frac{1}{2}m \frac{F^{2}t^{2}}{m^{2}} = \frac{F^{2}t^{2}}{2m}$.

$A$ body initially at rest is acted upon by a constant force $F$ for time $t$. The kinetic energy at time $t$ is

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