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(D) The total number of possible outcomes when two dice are rolled is $6 	imes 6 = 36$.The product of the numbers on the two dice is odd if and only

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$\frac{3}{4}$

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(D) The total number of possible outcomes when two dice are rolled is $6 	imes 6 = 36$.The product of the numbers on the two dice is odd if and only if both numbers are odd. The odd numbers on a die are ${1, 3, 5}$.The number of outcomes where both dice show an odd number is $3 	imes 3 = 9$. These outcomes are $(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5)$.The product is even in all other cases. Therefore,the number of favorable outcomes is $36 - 9 = 27$.The probability that the product is even is $\frac{27}{36} = \frac{3}{4}$.

Two balanced dice are rolled simultaneously. The probability that the product of numbers on two dice is even is ......

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