If $P(A) = 0.54$,then $P(\overline{A}) = \ldots$

The probability of a non-leap year having $53$ Fridays is $\ldots \ldots \ldots$

Two balanced dice are rolled. Find the probability that the sum of numbers on two dice is a multiple of $5$.

$A$ bag contains $24$ balls of which $x$ are red,$2x$ are white,and $3x$ are blue. $A$ ball is selected at random. What is the probability that it is:
$(i)$ not red?
$(ii)$ white?

If $P(A) : P(\bar{A}) = 3 : 4$,then $P(A) =$ .........

$A$ balanced die is rolled twice. Then,the probability of the event that the sum of the numbers received in two trials is more than $10$ is ...........