The correct order of bond angle is:
- A$H_2O > H_2S > H_2Se > H_2Te$
- B$H_2Te > H_2Se > H_2S > H_2O$
- C$H_2S > H_2O > H_2Se > H_2Te$
- D$H_2O > H_2S > H_2Te > H_2Se$
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Similar Questions
Match the molecular geometries in List-$I$ with their corresponding molecules in List-$II$:
$A$. Trigonal planar $I$. $PCl_5$ $B$. Tetrahedral $II$. $SF_6$ $C$. Trigonal bipyramidal $III$. $BF_3$ $D$. Octahedral $IV$. $CCl_4$
The correct match for $A, B, C, D$ is:
| $A$. Trigonal planar | $I$. $PCl_5$ |
| $B$. Tetrahedral | $II$. $SF_6$ |
| $C$. Trigonal bipyramidal | $III$. $BF_3$ |
| $D$. Octahedral | $IV$. $CCl_4$ |
The correct match for $A, B, C, D$ is:
Select the correct matching:
List-$I$ List-$II$ $A$. $XeF_4$ $1$. Pyramidal $B$. $XeF_6$ $2$. $T$-shape $C$. $XeO_3$ $3$. Distorted octahedral $D$. $XeOF_2$ $4$. Square planar
| List-$I$ | List-$II$ |
|---|---|
| $A$. $XeF_4$ | $1$. Pyramidal |
| $B$. $XeF_6$ | $2$. $T$-shape |
| $C$. $XeO_3$ | $3$. Distorted octahedral |
| $D$. $XeOF_2$ | $4$. Square planar |
Difficult
View SolutionWhich of the following is the correct order of bond angle?
Medium
View SolutionThe correct order of increasing bond angles is
Difficult
View SolutionMatch List-$I$ with List-$II$ :
List-$I$ List-$II$ $A$. $H_3O^+$ $I$. Tetrahedral $B$. Acetylide anion $II$. Linear $C$. $NH_4^+$ $III$. Pyramidal $D$. $ClO_2^-$ $IV$. Bent
Choose the correct answer from the options given below :
| List-$I$ | List-$II$ |
|---|---|
| $A$. $H_3O^+$ | $I$. Tetrahedral |
| $B$. Acetylide anion | $II$. Linear |
| $C$. $NH_4^+$ | $III$. Pyramidal |
| $D$. $ClO_2^-$ | $IV$. Bent |
Choose the correct answer from the options given below :
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