Which of the following is the correct order o | vedclass

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(C) The central atom in $NH_3$ and $NF_3$ undergoes $sp^3$ hybridization,resulting in a pyramidal geometry with one lone pair and three bond pairs.In

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$NH_3 > NF_3 > PH_3$

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(C) The central atom in $NH_3$ and $NF_3$ undergoes $sp^3$ hybridization,resulting in a pyramidal geometry with one lone pair and three bond pairs.In $NH_3$,the bond pairs are closer to the nitrogen atom,leading to greater repulsion between them compared to $NF_3$,where the highly electronegative fluorine atoms pull the electron density away from the nitrogen.Consequently,the bond angle in $NH_3$ $(107^{\circ})$ is greater than in $NF_3$ $(102^{\circ})$.In $PH_3$,the central atom $P$ is larger and less electronegative,and the molecule involves almost pure $p$-orbitals for bonding,resulting in a bond angle close to $92^{\circ}$.Thus,the correct order of bond angle is $NH_3 > NF_3 > PH_3$.

Which of the following is the correct order of bond angle?

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