What is the total number of planes in CH_4 th | vedclass

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(C) In a methane molecule $(CH_4)$,the carbon atom is $sp^3$ hybridized,resulting in a tetrahedral geometry. To find the number of planes containing t

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) In a methane molecule $(CH_4)$,the carbon atom is $sp^3$ hybridized,resulting in a tetrahedral geometry. To find the number of planes containing the maximum number of atoms (which is $3$ atoms in this case),we consider the combinations of atoms: $1$. Planes containing $3$ atoms: Any $3$ atoms in a molecule define a plane. In $CH_4$,there are $4$ atoms of Hydrogen and $1$ atom of Carbon. The number of ways to choose $3$ atoms out of $5$ is given by $^5C_3 = \frac{5 	imes 4}{2 	imes 1} = 10$. $2$. These $10$ planes consist of: - $6$ planes formed by $H-C-H$ bonds. - $4$ planes formed by $H-H-H$ combinations. Thus,the total number of such planes is $10$.

What is the total number of planes in $CH_4$ that contain the maximum number of atoms?

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