In the formation of a molecule by atoms,which forces operate?
- AAttractive forces operate
- BRepulsive forces operate
- CBoth attractive and repulsive forces operate
- DNone of these
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$BCl_3$ does not exist as a dimer,but $BH_3$ exists as a dimer $(B_2H_6)$ because:
MediumAIIMS 2012
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View SolutionMatch the following columns:
Column-$I$ Column-$II$ $(P)$ $\underline PCl_5 \to PCl_3 + Cl_2$ $(i)$ Change in hybridisation $(Q)$ $\underline SO_3 \to \underline SO_2 + \frac{1}{2}O_2$ $(ii)$ Change in bond angle $(R)$ $\underline NH_3 + H^{+} \to \underline NH_4^+$ $(iii)$ Change in shape $(S)$ $H_2\underline O + H^{+} \to H_3\underline O^{+}$ $(iv)$ Change in oxidation state
| Column-$I$ | Column-$II$ |
| $(P)$ $\underline PCl_5 \to PCl_3 + Cl_2$ | $(i)$ Change in hybridisation |
| $(Q)$ $\underline SO_3 \to \underline SO_2 + \frac{1}{2}O_2$ | $(ii)$ Change in bond angle |
| $(R)$ $\underline NH_3 + H^{+} \to \underline NH_4^+$ | $(iii)$ Change in shape |
| $(S)$ $H_2\underline O + H^{+} \to H_3\underline O^{+}$ | $(iv)$ Change in oxidation state |
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View SolutionAssertion : Bond angle of $H_2S$ is smaller than $H_2O$.
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Reason : Electronegativity of the central atom increases,bond angle decreases.
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