(C) The electronic configuration given is $[Ar] 3d^5 4s^2$. For $d-$block elements,the group number is calculated as the number of electrons in $(n-1)

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(C) The electronic configuration given is $[Ar] 3d^5 4s^2$. For $d-$block elements,the group number is calculated as the number of electrons in $(n-1)d$ subshell + number of electrons in $ns$ subshell. Here,$n=4$. Number of electrons in $3d = 5$. Number of electrons in $4s = 2$. Group number $= 5 + 2 = 7$. Thus,the element belongs to the $7^{th}$ group of the periodic table.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Extended or long form of periodic table

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To which group of the periodic table does an element having electronic configuration $[Ar] 3d^5 4s^2$ belong?

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Classification of Elements and Periodicity in Properties

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Extended or long form of periodic table

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To which group of the periodic table does an element having electronic configuration $[Ar] 3d^5 4s^2$ belong?

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