To compare magnetic moments of two magnets by vibration magnetometer, 'sum and difference method' is better because
To compare magnetic moments of two magnets by vibration magnetometer, 'sum and difference method' is better because
- A
Determination of moment of inertia is not needed which minimises the errors
- B
Less observations are required
- C
Comparatively less calculations
- D
All the above
Similar Questions
A tangent galvanometer shows a deflection $45^o $ when $10\, mA$ current pass through it. If the horizontal component of the earth’s field is $3.6 \times {10^{ - 5}}\,T$ and radius of the coil is $10\, cm$. The number of turns in the coil is......$turns$
A tangent galvanometer shows a deflection $45^o $ when $10\, mA$ current pass through it. If the horizontal component of the earth’s field is $3.6 \times {10^{ - 5}}\,T$ and radius of the coil is $10\, cm$. The number of turns in the coil is......$turns$
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A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is $4\, sec$. If one of the magnets is taken away, find the period of oscillation of the other in the same field (in $sec.$) :-
A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is $4\, sec$. If one of the magnets is taken away, find the period of oscillation of the other in the same field (in $sec.$) :-